Parasykite algoritma sumai 1x3+3x5+....+n x(n+2) apskaiciuoti, kai n - nelyginis naturalusis skaicius. (x - daugybos zenklas) Turetu buti kazkas panasaus i sita :) Aciu, kas parasys! program algoritmas; var S, n, d, i :longint; begin WriteLn('Iveskite n'); WriteLn; Readln(n); WriteLn; S:= 0; d:= 1; for i:= 1 to n do begin S:= S + d; d:= d * 10+1 end; WriteLn; WriteLn ('Suma = ', S); WriteLn; ReadLn; end.