Jquey ir klaidos pranesimas

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Niekaip nepavyksta gauti klaidos pranesimo su ajax jquery. Gal galite padeti?

82.196.2.74/TrackerV2/function.php?function=Login

if ($Email == null) {
           header('HTTP/1.1 403 Forbidden');
           echo "Empty Email";
           break;
       }

<div id="LoginPage" style="display: block; width:300px;margin-left: auto; margin-right: auto;">
       <div class="SiginContainer">
           <center>
               <form id="LoginForm" class="form-signin" action="" method="post" >
                   <h2 class="form-signin-heading"><? echo $Singin; ?></h2>
                   <input type="text" name="Email" id="Email"  class="input-block-level" placeholder="<? echo $Email; ?>">
                   <input type="password" name="Password" id="Password" class="input-block-level" placeholder="<? echo $Password; ?>">
                   <div class="alert alert-error" style="display:none">  
                       <a class="close" data-dismiss="alert">×</a>  
                       <strong><? echo $Error; ?></strong><? echo $WrongLogin; ?>  
                   </div>  
                   <button id="LoginFormSubmit" class="btn btn-large btn-primary" data-loading-text="Loading..." type="submit">Sign in</button>
               </form>
           </center>      
       </div>        
   </div>

   <script>
 $('#LoginForm').submit(function(e) {e.preventDefault();
  $.ajax({
  type: "POST",
  url: 'function.php?function=Login',
  data: $(this).serialize(),
  dataType: 'json',
  success: function(data){alert(data.toString());},
  statusCode: {403: function(e) {alert(e.toString());}}

 });
});

Firefox ir Chrome turi konsolę, kuri parodo visas klaidas. Įsijunk ją ir nereikės klaidų gaudyti pačiame kode. Aišku, jeigu tas klaidas nori matyti tik tu. Kitu atveju gali pasižiūrėti čia http://stackoverflow.com/questions/377644/jquery-ajax-error-handling-show-custom-exception-messages