php kategorijos info index'e rodo, o paspaudus ne

Man reikia, kad ten kur padariau, kad įrašyčiau skelbimą, man skelbimo info rodytų ne tik index.php, bet ir paspaudus ant to skelbimo antraštės,prašau, padėkit..

ĮDĖJIMAS:

<?php

if(isset($_POST['name'], $_POST['description']) and $_POST['name']!='')

{

$name = $_POST['name'];

$description = $_POST['description'];

if(get_magic_quotes_gpc())

{

$name = stripslashes($name);

$description = stripslashes($description);

}

$name = mysql_real_escape_string($name);

$description = mysql_real_escape_string($description);

if(mysql_query('insert into categories (id, name, description, position) select ifnull(max(id), 0)+1, "'.$name.'", "'.$description.'", count(id)+1 from categories'))

{

?>

<div class="message">Skelbimas sėkmingai įdėtas, jį galima pamatyti pagrindiniame puslapyje.<br />

<a href="<?php echo $url_home; ?>">Pagrindinis puslapis</a></div>

<?php

}

else

{

echo 'An error occured while creating the category.';

}

}

else

{

?>

<form action="add_ad.php" method="post">

<label for="name">Pavadinimas</label><input type="text" name="name" id="name" /><br />

<label for="description">Aprašymas</label><br />

<textarea name="description" id="description" cols="70" rows="6"></textarea><br />

<input type="submit" value="Create" />

</form>

<?php

}

INDEX`E

<table

>

<tr>

<th

>Skelbimas</th>

</tr>

<tr>

<?php

$dn1 = mysql_query('select c.id, c.name, c.description, c.position, (select count(t.id) from topics as t where t.parent=c.id and t.id2=1) as topics, (select count(t2.id) from topics as t2 where t2.parent=c.id and t2.id2!=1) as replies from categories as c group by c.id order by c.position asc');

$nb_cats = mysql_num_rows($dn1);

while($dnn1 = mysql_fetch_array($dn1))

{

?>

<td><a href="ad.php?parent=<?php echo $dnn1['id']; ?>" class="title"><?php echo htmlentities($dnn1['name'], ENT_QUOTES, 'UTF-8'); ?></a>

<div class="description"><?php echo $dnn1['description']; ?></div></td>

</tr>

<?php

}

?>

</table>

http://image.prntscr.com/image/1965be794ddb44b1a559193d39ee2769.png

O dabar ka meta? Ir siaip naudok geriau mysqli :)

O dabar ka meta? Ir siaip naudok geriau mysqli :)

Nieko, nepavyksta paleist skelbimo. Vis mėginu ir nieko.

<a href="ad.php?parent=<?php echo $dnn1['id']; ?>" class="title"><?php echo htmlentities($dnn1['name'], ENT_QUOTES, 'UTF-8'); ?></a> 

sita vieta perasyti galima bandyti sitaip, jei gerai supratau kad nuoroda blogai nukreipia

<?php echo "<a href='ad.php?parent=".$dnn1['id']."' class='title'>". htmlentities($dnn1['name'], ENT_QUOTES, 'UTF-8') ."</a>";?>