Reikia pagelbos dėl SQL

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Nu žodžiu meta tokį erora:

DB Error: Bad SQL Query: SELECT i.image_id, i.cat_id, i.user_id, i.image_name, i.image_description, i.image_keywords, i.image_date, i.image_active, i.image_media_file, i.image_thumb_file, i.image_download_url, i.image_allow_comments, i.image_comments, i.image_downloads, i.image_votes, i.image_rating, i.image_hits, c.cat_name, u.user_name FROM 4images_images i, 4images_categories c LEFT JOIN 4images_users u ON (u.user_id = i.user_id) WHERE i.image_active = 1 AND i.cat_id = 3 AND c.cat_id = i.cat_id ORDER BY image_date DESC LIMIT 0, 16
Unknown column 'i.user_id' in 'on clause'

O čia failo iškarpa kur mano manymu galėtų būti problema (nors aš čia tik spėju)...

//-----------------------------------------------------
//--- Show Images -------------------------------------
//-----------------------------------------------------
$num_rows_all = (isset($cat_cache[$cat_id]['num_images'])) ? $cat_cache[$cat_id]['num_images'] : 0;
$link_arg = $site_sess->url(ROOT_PATH."categories.php?".URL_CAT_ID."=".$cat_id);

include(ROOT_PATH.'includes/paging.php');
$getpaging = new Paging($page, $perpage, $num_rows_all, $link_arg);
$offset = $getpaging->get_offset();

$site_template->register_vars(array(
 "paging" => $getpaging->get_paging(),
 "paging_stats" => $getpaging->get_paging_stats()
));

$imgtable_width = ceil((intval($config['image_table_width'])) / $config['image_cells']);
if ((substr($config['image_table_width'], -1)) == "%") {
 $imgtable_width .= "%";
}

$additional_sql = "";
if (!empty($additional_image_fields)) {
 foreach ($additional_image_fields as $key => $val) {
$additional_sql .= ", i.".$key;
 }
}

$sql = "SELECT i.image_id, i.cat_id, i.user_id, i.image_name, i.image_description, i.image_keywords, i.image_date, i.image_active, i.image_media_file, i.image_thumb_file, i.image_download_url, i.image_allow_comments, i.image_comments, i.image_downloads, i.image_votes, i.image_rating, i.image_hits".$additional_sql.", c.cat_name".get_user_table_field(", u.", "user_name")."
	FROM (".IMAGES_TABLE." i,  ".CATEGORIES_TABLE." c)
	LEFT JOIN ".USERS_TABLE." u ON (".get_user_table_field("u.", "user_id")." = i.user_id)
	WHERE i.image_active = 1 AND i.cat_id = $cat_id AND c.cat_id = i.cat_id
	ORDER BY ".$config['image_order']." ".$config['image_sort']."
	LIMIT $offset, $perpage";
$result = $site_db->query($sql);
$num_rows = $site_db->get_numrows($result);

if (!$num_rows)  {
 $thumbnails = "";
 $msg = $lang['no_images'];
}
else {
 $thumbnails = "<table width=\"".$config['image_table_width']."\" border=\"0\" cellpadding=\"".$config['image_table_cellpadding']."\" cellspacing=\"".$config['image_table_cellspacing']."\">\n";
 $count = 0;
 $bgcounter = 0;
 while ($image_row = $site_db->fetch_array($result)){
if ($count == 0) {
  $row_bg_number = ($bgcounter++ % 2 == 0) ? 1 : 2;
  $thumbnails .= "<tr class=\"imagerow".$row_bg_number."\">\n";
}
$thumbnails .= "<td width=\"".$imgtable_width."\" valign=\"top\">\n";

show_image($image_row);
$thumbnails .= $site_template->parse_template("thumbnail_bit");
$thumbnails .= "\n</td>\n";

$count++;
if ($count == $config['image_cells']) {
  $thumbnails .= "</tr>\n";
  $count = 0;
}
 } // end while

 if ($count > 0)  {
$leftover = ($config['image_cells'] - $count);
if ($leftover > 0) {
  for ($i = 0; $i < $leftover; $i++){
	$thumbnails .= "<td width=\"".$imgtable_width."\">\n \n</td>\n";
  }
  $thumbnails .= "</tr>\n";
}
 }
 $thumbnails .= "</table>\n";
} //end else
$site_template->register_vars("thumbnails", $thumbnails);
unset($thumbnails);

Taigi ka patartumėt kas gali būti ir kaip man išspresti problemą...

Vsio jau susitvarkiau B)

Čia skliaustelių reikėjo:

FROM (".IMAGES_TABLE." i,  ".CATEGORIES_TABLE." c)

Visa diena laužiau galva kaip čia kas ir kodėl, o čia bliamba tik sušiktu skliaustelių reikėjo <_<